length = byteArray.size.toULong()
Range queries ask "what's inside this box?" But sometimes the question is "what's nearest to this location?" This is the nearest neighbor problem, and you don't know how big your search radius should be. The nearest point might be right next to you or far away.
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几何体:骨架,决定了形状(是方的、圆的,还是扭曲的)。